> Wow, how did I miss the TI parts?
>
> Looked everywhere else, and I was sort of stuck between a $1.20 national
> part w/shunt, and the Allegro part... The INA21X's have too low of a
> CMRR voltage, but the INA270 looks like it might be perfect for the job.
>
> Thanks!
>
> -forrest
>
> On 6/23/2011 12:39 PM, Mark E. Skeels wrote:
>> Forest,
>>
>> It might be worth investigating using a very small series resistor with
>> a TI INA21X. current shunt monitor.
>>
>> focus.ti.com/docs/prod/folders/print/ina214.html
>>
>> The chip output reference can be attached to something other than ground
>> and the small value resistor needed allows very low insertion loss and
>> low wattage rating.
>>
>> Different parts in the family have different gains, so you can choose
>> one that fits your needs.
>>
>> Data sheet:
http://focus.ti.com/lit/ds/symlink/ina214.pdf
>>
>> I can't spend a lot of time to see if this really fits your app, but I
>> thought I'd mention it here because I bet if you take a look you'll find
>> a nice way to use it and I suspect it will save you some $ over the
>> Allegro part.
>>
>> Just make sure you have dedicated sense lead connections to the inputs
>> to avoid voltage drop in the main current path which leads to errors. If
>> you do this right you can get good results.
>>
>>> Mark Skeels
>>> Engineer
>>> Competition Electronics, Inc.
>>> TEL: 815-874-8001
>>> FAX: 815-874-8181
>>>
http://www.competitionelectronics.com
>>> On 6/23/2011 11:38 AM, Michael Watterson wrote:
>>>> what is resolution of ADC compared to accuracy of the sensor? Does it
>>>> actually matter if full adc range isn't used? If so save on HW and just
>>>> scale in SW. Unless you use precision resistors etc adding an op-amp may
>>>> reduce accuracy?
>>> I'm going to be using a 10 bit ADC in a PIC. Vdd/Vss references, 3.3V
>>> So 3.3/1024 = ~3mV/step.
>>>
>>> For various reasons (primarily increasing the number of places this part
>>> can be used), i'd really like to use the +-25A version of the Allegro
>>> product. In this case, I'm most interested in 0-+5A.
>>>
>>> 0A corresponds to 1.67V. 5A corresponds to (5*0.055+1.67)= 1.945V.
>>> So, a range of 275ma over the range of interest... or just under 100
>>> steps.
>>>
>>> Or using the other math... 55mV per AMP, or about 1/20th of an amp per
>>> step. Not sure that is enough resolution for me.
>>>
>>> I was considering moving the ADC references but there just isn't enough
>>> to gain - you need at least 2V from Vref+ to Vref-, which means I'd be
>>> lucky to gain another 100 steps.
>>>
>>> Although I have to admit, the most usable option I've come up with so
>>> far is to give up and use the 12.5A version, and move the Vref- to
>>> around 1.2V, which should put us at 2.1V/1024 = 2mV/step, and the about
>>> 55 steps/amp... or 0.02A per 'step', which seems quite a bit better, and
>>> then do math in software to get the right values.
>>>
>>> -forrest