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2002\01\17@180130 by

I have here "RF Circuit Design" by Chris Bowick.

In chapter 3, Impedance Matching, one of his solutions os pretty sketchy...

I understand everything except the jump from 2 to 3...it seems to be missing some steps because I don't believe you can convert directly to polar notation from a product over sum.

How does he jump from step 2 to 3?

Xc = Capacitive Reactance

1.
XcRl
Z = -------
Xc + Rl

2.
-j333(1000)
= ------------
-j333 + 1000

3.
= 315 at -71.58 degrees

4.
= 100 - j3000 Ohms

Thanks for any help...

Brandon Irwin

-
end

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1)    A bit of math, try to multiply iten 2 by (+j333+1000) / (+j333+1000)
as both values are equal you are multiplying by one, so you don't change the
original value.

you will end with

-j333(1000) * (+j333 +1000)
= ------------------------------
(-j333 + 1000) * (j333 +1000)

111088900 - j333000000
= -----------------------------
1110889

=  100 -j299.76

= 315 -71.58 degrees  in polar notation

Note: iten 4 has an error it's 100 -j299.76 (or -j300 by rounding)
not -j3000

I assume you know complex number algebra, let me know if you need
anything else.
This book is really amasing, enjoy it.

Regards
Horta

wich in polar form is
{Original Message removed}

Have a look at articles 12 and 13 at
http://www.hallikainen.org/rw/theory/

Harold

On Thu, 17 Jan 2002 14:57:08 -0800 Brandon Irwin <brandonE-HA.COM>
writes:
{Quote hidden}

FCC Rules Online at http://hallikainen.com/FccRules
Lighting control for theatre and television at http://www.dovesystems.com

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