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'I/O Impedance'
1998\03\26@142613 by ERIC SCHLAEPFER

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Hello,

Does anyone know the input and output impedance of each I/O line in PORTB
of a 16F84? I can't find it in the data sheet.

Thanks in advance,

Eric

1998\03\27@010950 by Leon Heller

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In message <spam_OUT0043C076.4149TakeThisOuTspamautodesk.com>, ERIC SCHLAEPFER
<.....eric.schlaepferKILLspamspam@spam@AUTODESK.COM> writes
>Hello,
>
>Does anyone know the input and output impedance of each I/O line in PORTB
>of a 16F84? I can't find it in the data sheet.

I don't think that impedance is very meaningful in this context, which
is why it isn't quoted. The AC output impedance is probably highly
frequency- and load-dependent, unlike a linear amplifier. I've checked
through some of the different manufacturers' data I've got, and can't
find any who specify it. You could probably model it for a given set of
conditions, if you knew the characteristics of the input/output devices.
Inmos used SPICE simulation to characterise the transistors used in the
transputer, for instance.

I've just looked at the data for a VHF mixer device. This is an analogue
chip, and the mixer input impedance varies quite a lot over the design
frequency range. Digital devices would be much messier.

Leon
--
Leon Heller: leonspamKILLspamlfheller.demon.co.uk http://www.lfheller.demon.co.uk
Amateur Radio Callsign G1HSM    Tel: +44 (0) 118 947 1424
See http://www.lfheller.demon.co.uk/dds.htm for details of my AD9850
DDS system. See " "/diy_dsp.htm for a simple DIY DSP ADSP-2104 system.

1998\03\27@164551 by Mike Keitz

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On Thu, 26 Mar 1998 11:26:14 -0800 ERIC SCHLAEPFER
<.....eric.schlaepferKILLspamspam.....AUTODESK.COM> writes:
>Hello,
>
>Does anyone know the input and output impedance of each I/O line in
>PORTB
>of a 16F84? I can't find it in the data sheet.

A DC "input impedance" can be inferred from the specified DC leakage
current.  The specification is about 1uA.  Depending on the chip
conditions, the current may leak from any voltage between Vss and Vdd.
Assuming the worst case, such as input at Vdd and all leakage current to
Vss, with 5V Vdd an equivalent input circuit would be a resistance of
5V/1uA = 5 M ohm.  So it is somewhat useful to declare that the input
impedance (for input voltages between Vss and Vdd) is 5M ohm or more.

A small-signal output impedance can be derived from the slope of the Vout
versus Iout curves in the data sheet.  The curves vary widely depending
on Vdd, Ta, and Vout.  When the output is driving "high", it has a lot
more impedance than when it is driving "low".  Consider a worst-case of
5V, Ta=85C.  The high-level output voltage drops 1V (from 5V to 4V) with
approximately 3 mA of output current.  So the output impedance is about
1V/3 mA = 330 ohms.  This is very much a worst-case.  Under most
conditions it will be much less.

Also there is a capacitance of about 5 pF per pin that should be factored
into the impedance for high-frequency signals.


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