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'Re[2]: [EE:] How do you create and understand circ'
2007\01\29@070808 by

LM> Thank you _very_ much, Olin, for taking the time to explain this in your own way.  I was actually hoping you would answer because I know you also teach electronics and I figured you'd have a good
LM> insight on ways to help someone along.
LM> I'll really give your circuit a good look. But so far no one has answered my question on how/where to start.  Do I start at the + power supply and then make my way through all the components
LM> imagining in what "state" the current is in as it passes through each piece?
LM> Lindy

I started learning electronics as a hobby two years ago. I was just
like you and i am still a beginner. Also i used x86 assembly for a
long long time and i came from programming world. I can tell you
exactly what made the things easy for me : the resistor :-)
Yes, you read correctly. Just like Olin said i just tried to
understand the resistor in all possible ways and from that point on it
was just easy. Let me put it this way :
The current will follow the shortest path rather than the longest one.
A resistor is in simple words a longer path than a straight wire.
If you have a junction with two possibilities ahead : one 10k resistor
and a 1k resistor the current will go to the 1k path since 1k "road"
is shorter that the 10k "road". I hope you get it like i did, is
really simple. This way you can quickly see how a pull-down or a
pull-up resistor works. Try keeping the shortest-road in your head
when looking at circuits and you will see really soon some improvments
:)
For me it was this simple...

>one 10k resistor and a 1k resistor the current will go to
>the 1k path since 1k "road" is shorter that the 10k "road".

Just don't forget that some electrons still like to take the "cross country
long way round scenic" route ;)

On 1/29/07, Dumitru Stama <listmirosat.com> wrote:
>
> If you have a junction with two possibilities ahead : one 10k resistor
> and a 1k resistor the current will go to the 1k path since 1k "road"
> is shorter that the 10k "road".
>
Not exactly:)  Some of the electricity will go through the 10k
resistor, most of it will go through the 1k.  IIRC, the formula is 1/R
= 1/R1 + 1/R2....  so 1/R = .001 + .0001, giving us 1/.0011 or 909
ohms.  The 1k and 10k resistors in parallel, will measure as 909 ohms
on a multimeter, and will be effectively the same as a single 909 ohm
resistor.

--
Paul Anderson
VE3HOP
wackyvorlongmail.com
http://www.oldschoolhacker.com
"May the electromotive force be with you."

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